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Solved triangle (right scalene)

A = 36.87°, B = 53.13°, C = 90°

Sides 3, 4, 5

Area
6
Perimeter
12
Type
right scalene
Sides a, b, c3, 4, 5
Angles A, B, C36.8699°, 53.1301°, 90°
Angles in radians0.6435, 0.9273, 1.5708
Heights hₐ, h_b, h_c4, 3, 2.4
Semi-perimeter s6
Inradius r = Area ÷ s1
Circumradius R = a ÷ (2 sin A)2.5
A 36.87°B 53.13°C 90°a = 3b = 4c = 5
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Step by step

  1. Law of cosines: A = arccos((b² + c² − a²) ÷ 2bc) = arccos((4² + 5² − 3²) ÷ (2 × 4 × 5)) = 36.8699°
  2. B = arccos((a² + c² − b²) ÷ 2ac) = 53.1301°
  3. C = 180° − A − B = 90°
  4. Area (Heron’s formula): √(s(s − a)(s − b)(s − c)) = √(6 × 3 × 2 × 1) = 6
  5. Perimeter: 3 + 4 + 5 = 12

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